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3월, 2017의 게시물 표시

python gnerator

The performance improvement from the use of generators is the result of the lazy (on demand) generation of values, which translates to lower memory usage. Furthermore, we do not need to wait until all the elements have been generated before we start to use them. This is similar to the benefits provided by iterators, but the generator makes building iterators easy from  https://wiki.python.org/moin/Generators Interesting thing!

Fyneman exercise I ch29-2

2. Four identical dipole radiators are aligned parallel to one another and are equally spaced along a line at a distance apart. They are driven at a frequency of and are phased so that, starting from one end, each successive dipole lags the preceding one by . Find the intensity pattern of the radiation at a great distance in the equatorial plane (perpendicular to the dipole axes), and sketch this function in polar coordinates. Such a diagram is called the radiation pattern of an antenna system. My ans. At fixed point in equatorial plane with angle from dipole radiators aligned line, Let phase diff each adjacent dipole = : , where . first method Field, Using complex, Intensity, , substitue (1) Notice Above eq.(1) is valid when i.e. When , from orignal Intensity eq. second method just using eq.(30.3) substitue , graph x: red, y: green Initial intensity :1 Intensity scale : 1000 distance > 100 This could

Fyneman exercise I ch29-1

1. Two antennas are arranged as shown in Fig. 29-5(a) and are driven in phase. The antennas are driven so that one would, if alone, radiate a certain intensity in all horizontal directions, and the other, an intensity . What should the observed intensities in the various directions shown in the figure be? My ans. Intensity is proportional to square of the field. So, means . N, S phase diff = , N60, S60 using eq.(29.17) phase diff = using eq. (29.16) substitute, E, W in phase, This could be wrong.

Fyneman exercise I ch28

1. Interpret the following two problems in complex numbers geometrically, and thus find absolute value of A in each case a) b) Ans a) b) Let radius of circle R(r in fig., but we have already r in problem. ), —-(1) —-(2) substitute (1) to (2)